q=translated+from+the+Swedish+by+Rod+Bradbury.&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&curlibcode=HPJY9745&searchWay0=marc&logical0=AND
rows=10&curlibcode=HPJY9745&searchWay0=marc&logical0=AND
translated from the Swedish by Rod Bradbury.