q=jacquet%5C-langlands%E7%90%86%E8%AE%BA%EF%BC%9A%5C%5B%E8%8B%B1%E6%96%87%E7%89%88%5C%5D&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&curlibcode=YT&searchWay0=marc&logical0=AND
rows=10&curlibcode=YT&searchWay0=marc&logical0=AND
Jacquet-Langlands理论：[英文版]