q=%28%E8%8B%B1%29bob+adamson%EF%BC%8C%28%E8%8B%B1%29graham+yo&searchType=standard&isFacet=true&view=standard&searchWay=author&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
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(英)Bob Adamson，(英)Graham Yo
